4x+3(x+1)=7(x+3)-5

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Solution for 4x+3(x+1)=7(x+3)-5 equation: 


Simplifying
4x + 3(x + 1) = 7(x + 3) + -5

Reorder the terms:
4x + 3(1 + x) = 7(x + 3) + -5
4x + (1 * 3 + x * 3) = 7(x + 3) + -5
4x + (3 + 3x) = 7(x + 3) + -5

Reorder the terms:
3 + 4x + 3x = 7(x + 3) + -5

Combine like terms: 4x + 3x = 7x
3 + 7x = 7(x + 3) + -5

Reorder the terms:
3 + 7x = 7(3 + x) + -5
3 + 7x = (3 * 7 + x * 7) + -5
3 + 7x = (21 + 7x) + -5

Reorder the terms:
3 + 7x = 21 + -5 + 7x

Combine like terms: 21 + -5 = 16
3 + 7x = 16 + 7x

Add '-7x' to each side of the equation.
3 + 7x + -7x = 16 + 7x + -7x

Combine like terms: 7x + -7x = 0
3 + 0 = 16 + 7x + -7x
3 = 16 + 7x + -7x

Combine like terms: 7x + -7x = 0
3 = 16 + 0
3 = 16

Solving
3 = 16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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