4x+3(x+2)=11+2(3-x)

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Solution for 4x+3(x+2)=11+2(3-x) equation: 



4x+3(x+2)=11+2(3-x)

We move all terms to the left:

4x+3(x+2)-(11+2(3-x))=0

We add all the numbers together, and all the variables

4x+3(x+2)-(11+2(-1x+3))=0

We multiply parentheses

4x+3x-(11+2(-1x+3))+6=0



We calculate terms in parentheses: -(11+2(-1x+3)), so:

11+2(-1x+3)

determiningTheFunctionDomain
2(-1x+3)+11

We multiply parentheses

-2x+6+11

We add all the numbers together, and all the variables

-2x+17

Back to the equation:

-(-2x+17)



We add all the numbers together, and all the variables

7x-(-2x+17)+6=0

We get rid of parentheses

7x+2x-17+6=0

We add all the numbers together, and all the variables

9x-11=0

We move all terms containing x to the left, all other terms to the right

9x=11

x=11/9

x=1+2/9

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