4x+3(x-1)=2(x-3)+9

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Solution for 4x+3(x-1)=2(x-3)+9 equation: 



4x+3(x-1)=2(x-3)+9

We move all terms to the left:

4x+3(x-1)-(2(x-3)+9)=0

We multiply parentheses

4x+3x-(2(x-3)+9)-3=0



We calculate terms in parentheses: -(2(x-3)+9), so:

2(x-3)+9

We multiply parentheses

2x-6+9

We add all the numbers together, and all the variables

2x+3

Back to the equation:

-(2x+3)



We add all the numbers together, and all the variables

7x-(2x+3)-3=0

We get rid of parentheses

7x-2x-3-3=0

We add all the numbers together, and all the variables

5x-6=0

We move all terms containing x to the left, all other terms to the right

5x=6

x=6/5

x=1+1/5

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