4x+3*((195-3x)/2)=275

Solution for 4x+3*((195-3x)/2)=275 equation:

4x+3((195-3x)/2)=275

We move all terms to the left:

4x+3((195-3x)/2)-(275)=0

We add all the numbers together, and all the variables

4x+3((-3x+195)/2)-275=0

We multiply all the terms by the denominator


4x*2)+3((-3x+195)-275*2)=0

We add all the numbers together, and all the variables

4x*2)+3((-3x+195)=0

Wy multiply elements

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$