4x+3-((15-8x)/2x)=0

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Solution for 4x+3-((15-8x)/2x)=0 equation:



4x+3-((15-8x)/2x)=0
Domain of the equation: 2x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
4x-((-8x+15)/2x)+3=0
We multiply all the terms by the denominator
4x*2x)-((-8x+15)+3*2x)=0
Wy multiply elements
8x^2+6x=0
a = 8; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·8·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*8}=\frac{-12}{16} =-3/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*8}=\frac{0}{16} =0 $

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