4x+3-4=8(1/2x+1)

Solution for 4x+3-4=8(1/2x+1) equation:

4x+3-4=8(1/2x+1)

We move all terms to the left:

4x+3-4-(8(1/2x+1))=0


Domain of the equation: 2x+1))!=0

x∈R


We add all the numbers together, and all the variables

4x-(8(1/2x+1))-1=0

We multiply all the terms by the denominator


4x*2x-1*2x+1))-(8(1+1))=0

We add all the numbers together, and all the variables

4x*2x-1*2x+1))-(82)=0

We add all the numbers together, and all the variables

4x*2x-1*2x=0

Wy multiply elements

8x^2-2x=0

a = 8; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·8·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*8}=\frac{0}{16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*8}=\frac{4}{16}
=1/4
$