4x+3-5=7(x-2)

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Solution for 4x+3-5=7(x-2) equation: 



4x+3-5=7(x-2)

We move all terms to the left:

4x+3-5-(7(x-2))=0

We add all the numbers together, and all the variables

4x-(7(x-2))-2=0



We calculate terms in parentheses: -(7(x-2)), so:

7(x-2)

We multiply parentheses

7x-14

Back to the equation:

-(7x-14)



We get rid of parentheses

4x-7x+14-2=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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