4x+35-15=9(x-5)

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Solution for 4x+35-15=9(x-5) equation: 



4x+35-15=9(x-5)

We move all terms to the left:

4x+35-15-(9(x-5))=0

We add all the numbers together, and all the variables

4x-(9(x-5))+20=0



We calculate terms in parentheses: -(9(x-5)), so:

9(x-5)

We multiply parentheses

9x-45

Back to the equation:

-(9x-45)



We get rid of parentheses

4x-9x+45+20=0

We add all the numbers together, and all the variables

-5x+65=0

We move all terms containing x to the left, all other terms to the right

-5x=-65

x=-65/-5

x=+13

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