4x+36=(2x-6)(2x-6)

Solution for 4x+36=(2x-6)(2x-6) equation:

4x+36=(2x-6)(2x-6)

We move all terms to the left:

4x+36-((2x-6)(2x-6))=0

We multiply parentheses ..

-((+4x^2-12x-12x+36))+4x+36=0


We calculate terms in parentheses: -((+4x^2-12x-12x+36)), so:

(+4x^2-12x-12x+36)

We get rid of parentheses

4x^2-12x-12x+36

We add all the numbers together, and all the variables

4x^2-24x+36

Back to the equation:

-(4x^2-24x+36)


We add all the numbers together, and all the variables

4x-(4x^2-24x+36)+36=0

We get rid of parentheses

-4x^2+4x+24x-36+36=0

We add all the numbers together, and all the variables

-4x^2+28x=0

a = -4; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-4)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-4}=\frac{-56}{-8}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-4}=\frac{0}{-8}
=0
$