4x+38+3x=8(1x+4)

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Solution for 4x+38+3x=8(1x+4) equation: 



4x+38+3x=8(1x+4)

We move all terms to the left:

4x+38+3x-(8(1x+4))=0

We add all the numbers together, and all the variables

4x+3x-(8(x+4))+38=0

We add all the numbers together, and all the variables

7x-(8(x+4))+38=0



We calculate terms in parentheses: -(8(x+4)), so:

8(x+4)

We multiply parentheses

8x+32

Back to the equation:

-(8x+32)



We get rid of parentheses

7x-8x-32+38=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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