4x+38=2(1+8x)

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Solution for 4x+38=2(1+8x) equation:



4x+38=2(1+8x)
We move all terms to the left:
4x+38-(2(1+8x))=0
We add all the numbers together, and all the variables
4x-(2(8x+1))+38=0
We calculate terms in parentheses: -(2(8x+1)), so:
2(8x+1)
We multiply parentheses
16x+2
Back to the equation:
-(16x+2)
We get rid of parentheses
4x-16x-2+38=0
We add all the numbers together, and all the variables
-12x+36=0
We move all terms containing x to the left, all other terms to the right
-12x=-36
x=-36/-12
x=+3

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