4x+3x(4-x)=0

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Solution for 4x+3x(4-x)=0 equation:



4x+3x(4-x)=0
We add all the numbers together, and all the variables
4x+3x(-1x+4)=0
We multiply parentheses
-3x^2+4x+12x=0
We add all the numbers together, and all the variables
-3x^2+16x=0
a = -3; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-3)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-3}=\frac{-32}{-6} =5+1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-3}=\frac{0}{-6} =0 $

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