4x+3x(4x+7)=4(7x+3)-3

Solution for 4x+3x(4x+7)=4(7x+3)-3 equation:

4x+3x(4x+7)=4(7x+3)-3

We move all terms to the left:

4x+3x(4x+7)-(4(7x+3)-3)=0

We multiply parentheses

12x^2+4x+21x-(4(7x+3)-3)=0


We calculate terms in parentheses: -(4(7x+3)-3), so:

4(7x+3)-3

We multiply parentheses

28x+12-3

We add all the numbers together, and all the variables

28x+9

Back to the equation:

-(28x+9)


We add all the numbers together, and all the variables

12x^2+25x-(28x+9)=0

We get rid of parentheses

12x^2+25x-28x-9=0

We add all the numbers together, and all the variables

12x^2-3x-9=0

a = 12; b = -3; c = -9;
Δ = b2-4ac
Δ = -32-4·12·(-9)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-21}{2*12}=\frac{-18}{24}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+21}{2*12}=\frac{24}{24}
=1
$