4x+3x2=24

Solution for 4x+3x2=24 equation:

4x+3x^2=24

We move all terms to the left:

4x+3x^2-(24)=0

a = 3; b = 4; c = -24;
Δ = b2-4ac
Δ = 42-4·3·(-24)
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{19}}{2*3}=\frac{-4-4\sqrt{19}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{19}}{2*3}=\frac{-4+4\sqrt{19}}{6}
$