4x+3y=3/2;3x-2y=-19/2

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2x+y=8
x+3y=14

Solution for 4x+3y=3/2;3x-2y=-19/2 system of equations: 


  • /| 4*x+3*y-(3/2) = 0| 3*x-(2*y)-(-19/2) = 0
  • We try to solve the equation: 4*x+3*y-(3/2) = 0
  • 4*x+3*y-3/2 = 0 // - 4*x-3/2
  • 3*y = -(4*x-3/2) // : 3
  • y = (-(4*x-3/2))/3
  • y = (3/2-(4*x))/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 3*x-(2*((3/2-(4*x))/3))-(-19/2) = 0| y = (3/2-(4*x))/3
  • (-1*2*(3/2-4*x))/3+3*x+19/2 = 0
  • 17/3*x-1+19/2 = 0
  • 17/3*x+17/2 = 0
  • 17/3*x+17/2 = 0 // - 17/2
  • 17/3*x = -17/2 // : 17/3
  • x = -17/2/17/3
  • x = -3/2
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (3/2-(4*x))/3: 
  • y = (3/2-(-3/2*4))/3
  • y = (3/2+6)/3
  • y = 15/2/3
  • y = 5/2
  • We get a system of equations:
  • /| y = 5/2| x = -3/2

 

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