4x+3y=4;x=35-5y

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Remember to put linear equations with variables x and y.
for example:
2x+y=8
x+3y=14

Solution for 4x+3y=4;x=35-5y system of equations: 


  • /| 4*x+3*y-4 = 0| x+5*y-35 = 0
  • We try to solve the equation: 4*x+3*y-4 = 0
  • 4*x+3*y-4 = 0 // - 4*x-4
  • 3*y = -(4*x-4) // : 3
  • y = (-(4*x-4))/3
  • y = (4-(4*x))/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 5*((4-(4*x))/3)+x-35 = 0| y = (4-(4*x))/3
  • (5*(4-4*x))/3+x-35 = 0
  • 20/3-17/3*x-35 = 0
  • -17/3*x-85/3 = 0
  • -17/3*x-85/3 = 0 // + 85/3
  • -17/3*x = 85/3 // : -17/3
  • x = 85/3/(-17/3)
  • x = -5
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (4-(4*x))/3: 
  • y = (4-(-5*4))/3
  • y = (4+20)/3
  • y = 24/3
  • y = 8
  • We get a system of equations:
  • /| y = 8| x = -5

 

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