4x+4(3x-11)=100

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Solution for 4x+4(3x-11)=100 equation: 



4x+4(3x-11)=100

We move all terms to the left:

4x+4(3x-11)-(100)=0

We multiply parentheses

4x+12x-44-100=0

We add all the numbers together, and all the variables

16x-144=0

We move all terms containing x to the left, all other terms to the right

16x=144

x=144/16

x=9

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