4x+4(x-3)-4(y-3)=

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Solution for 4x+4(x-3)-4(y-3)= equation:


Simplifying
4x + 4(x + -3) + -4(y + -3) = 0

Reorder the terms:
4x + 4(-3 + x) + -4(y + -3) = 0
4x + (-3 * 4 + x * 4) + -4(y + -3) = 0
4x + (-12 + 4x) + -4(y + -3) = 0

Reorder the terms:
4x + -12 + 4x + -4(-3 + y) = 0
4x + -12 + 4x + (-3 * -4 + y * -4) = 0
4x + -12 + 4x + (12 + -4y) = 0

Reorder the terms:
-12 + 12 + 4x + 4x + -4y = 0

Combine like terms: -12 + 12 = 0
0 + 4x + 4x + -4y = 0
4x + 4x + -4y = 0

Combine like terms: 4x + 4x = 8x
8x + -4y = 0

Solving
8x + -4y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4y' to each side of the equation.
8x + -4y + 4y = 0 + 4y

Combine like terms: -4y + 4y = 0
8x + 0 = 0 + 4y
8x = 0 + 4y
Remove the zero:
8x = 4y

Divide each side by '8'.
x = 0.5y

Simplifying
x = 0.5y

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