4x+4(x-5)=(2x-4)

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Solution for 4x+4(x-5)=(2x-4) equation: 



4x+4(x-5)=(2x-4)

We move all terms to the left:

4x+4(x-5)-((2x-4))=0

We multiply parentheses

4x+4x-((2x-4))-20=0



We calculate terms in parentheses: -((2x-4)), so:

(2x-4)

We get rid of parentheses

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

8x-(2x-4)-20=0

We get rid of parentheses

8x-2x+4-20=0

We add all the numbers together, and all the variables

6x-16=0

We move all terms containing x to the left, all other terms to the right

6x=16

x=16/6

x=2+2/3

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