4x+4(x-6)=8x-2(x-10)

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Solution for 4x+4(x-6)=8x-2(x-10) equation: 



4x+4(x-6)=8x-2(x-10)

We move all terms to the left:

4x+4(x-6)-(8x-2(x-10))=0

We multiply parentheses

4x+4x-(8x-2(x-10))-24=0



We calculate terms in parentheses: -(8x-2(x-10)), so:

8x-2(x-10)

We multiply parentheses

8x-2x+20

We add all the numbers together, and all the variables

6x+20

Back to the equation:

-(6x+20)



We add all the numbers together, and all the variables

8x-(6x+20)-24=0

We get rid of parentheses

8x-6x-20-24=0

We add all the numbers together, and all the variables

2x-44=0

We move all terms containing x to the left, all other terms to the right

2x=44

x=44/2

x=22

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