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4x+4-3x+8=1x+12
We move all terms to the left:
4x+4-3x+8-(1x+12)=0
We add all the numbers together, and all the variables
4x-3x-(x+12)+4+8=0
We add all the numbers together, and all the variables
x-(x+12)+12=0
We get rid of parentheses
x-x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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