4x+40=12x+32

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Solution for 4x+40=12x+32 equation: 



4x+40=12x+32

We move all terms to the left:

4x+40-(12x+32)=0

We get rid of parentheses

4x-12x-32+40=0

We add all the numbers together, and all the variables

-8x+8=0

We move all terms containing x to the left, all other terms to the right

-8x=-8

x=-8/-8

x=1

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