4x+40=4(1+4x)

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Solution for 4x+40=4(1+4x) equation: 



4x+40=4(1+4x)

We move all terms to the left:

4x+40-(4(1+4x))=0

We add all the numbers together, and all the variables

4x-(4(4x+1))+40=0



We calculate terms in parentheses: -(4(4x+1)), so:

4(4x+1)

We multiply parentheses

16x+4

Back to the equation:

-(16x+4)



We get rid of parentheses

4x-16x-4+40=0

We add all the numbers together, and all the variables

-12x+36=0

We move all terms containing x to the left, all other terms to the right

-12x=-36

x=-36/-12

x=+3

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