4x+4=(9x+4)/15

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Solution for 4x+4=(9x+4)/15 equation: 



4x+4=(9x+4)/15

We move all terms to the left:

4x+4-((9x+4)/15)=0

We multiply all the terms by the denominator


4x*15)-((9x+4)+4*15)=0

We add all the numbers together, and all the variables

4x*15)-((9x+4)=0

Wy multiply elements

60x^2=0

a = 60; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·60·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{120}=0$

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