4x+4=4x2

Solution for 4x+4=4x2 equation:

4x+4=4x^2

We move all terms to the left:

4x+4-(4x^2)=0

determiningTheFunctionDomain
-4x^2+4x+4=0

a = -4; b = 4; c = +4;
Δ = b2-4ac
Δ = 42-4·(-4)·4
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{5}}{2*-4}=\frac{-4-4\sqrt{5}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{5}}{2*-4}=\frac{-4+4\sqrt{5}}{-8}
$