4x+5(x-4)=4(x-2)-2

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Solution for 4x+5(x-4)=4(x-2)-2 equation: 



4x+5(x-4)=4(x-2)-2

We move all terms to the left:

4x+5(x-4)-(4(x-2)-2)=0

We multiply parentheses

4x+5x-(4(x-2)-2)-20=0



We calculate terms in parentheses: -(4(x-2)-2), so:

4(x-2)-2

We multiply parentheses

4x-8-2

We add all the numbers together, and all the variables

4x-10

Back to the equation:

-(4x-10)



We add all the numbers together, and all the variables

9x-(4x-10)-20=0

We get rid of parentheses

9x-4x+10-20=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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