4x+5+2x=6(x+3)-20

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Solution for 4x+5+2x=6(x+3)-20 equation: 



4x+5+2x=6(x+3)-20

We move all terms to the left:

4x+5+2x-(6(x+3)-20)=0

We add all the numbers together, and all the variables

6x-(6(x+3)-20)+5=0



We calculate terms in parentheses: -(6(x+3)-20), so:

6(x+3)-20

We multiply parentheses

6x+18-20

We add all the numbers together, and all the variables

6x-2

Back to the equation:

-(6x-2)



We get rid of parentheses

6x-6x+2+5=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation

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