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4x+5+9x=3-2(x-3)
We move all terms to the left:
4x+5+9x-(3-2(x-3))=0
We add all the numbers together, and all the variables
13x-(3-2(x-3))+5=0
We calculate terms in parentheses: -(3-2(x-3)), so:We get rid of parentheses
3-2(x-3)
determiningTheFunctionDomain -2(x-3)+3
We multiply parentheses
-2x+6+3
We add all the numbers together, and all the variables
-2x+9
Back to the equation:
-(-2x+9)
13x+2x-9+5=0
We add all the numbers together, and all the variables
15x-4=0
We move all terms containing x to the left, all other terms to the right
15x=4
x=4/15
x=4/15
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