4x+5-(3x-12)=120-6x(8-3x)

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Solution for 4x+5-(3x-12)=120-6x(8-3x) equation: 



4x+5-(3x-12)=120-6x(8-3x)

We move all terms to the left:

4x+5-(3x-12)-(120-6x(8-3x))=0

We add all the numbers together, and all the variables

4x-(3x-12)-(120-6x(-3x+8))+5=0

We get rid of parentheses

4x-3x-(120-6x(-3x+8))+12+5=0



We calculate terms in parentheses: -(120-6x(-3x+8)), so:

120-6x(-3x+8)

determiningTheFunctionDomain
-6x(-3x+8)+120

We multiply parentheses

18x^2-48x+120

Back to the equation:

-(18x^2-48x+120)



We add all the numbers together, and all the variables

x-(18x^2-48x+120)+17=0

We get rid of parentheses

-18x^2+x+48x-120+17=0

We add all the numbers together, and all the variables

-18x^2+49x-103=0

a = -18; b = 49; c = -103;
Δ = b2-4ac
Δ = 492-4·(-18)·(-103)
Δ = -5015
Delta is less than zero, so there is no solution for the equation

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