4x+5/3x+2=x-10/x-8

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Solution for 4x+5/3x+2=x-10/x-8 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x+(5/3)*x+2 = x-(10/x)-8 // - x-(10/x)-8

4*x+(5/3)*x-x+10/x+2+8 = 0

14/3*x^1+10*x^-1+10*x^0 = 0

(14/3*x^2+10*x^1+10*x^0)/(x^1) = 0 // * x^2

x^1*(14/3*x^2+10*x^1+10*x^0) = 0

x^1

(14/3)*x^2+10*x+10 = 0

(14/3)*x^2+10*x+10 = 0

DELTA = 10^2-(4*10*(14/3))

DELTA = -260/3

DELTA < 0

x in { } 

x belongs to the empty set

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