4x+50=(3x-10)+(5x+40)

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Solution for 4x+50=(3x-10)+(5x+40) equation: 



4x+50=(3x-10)+(5x+40)

We move all terms to the left:

4x+50-((3x-10)+(5x+40))=0



We calculate terms in parentheses: -((3x-10)+(5x+40)), so:

(3x-10)+(5x+40)

We get rid of parentheses

3x+5x-10+40

We add all the numbers together, and all the variables

8x+30

Back to the equation:

-(8x+30)



We get rid of parentheses

4x-8x-30+50=0

We add all the numbers together, and all the variables

-4x+20=0

We move all terms containing x to the left, all other terms to the right

-4x=-20

x=-20/-4

x=+5

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