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4x+5x(-2x)=-18
We move all terms to the left:
4x+5x(-2x)-(-18)=0
We add all the numbers together, and all the variables
4x+5x(-2x)+18=0
We multiply parentheses
-10x^2+4x+18=0
a = -10; b = 4; c = +18;
Δ = b2-4ac
Δ = 42-4·(-10)·18
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{46}}{2*-10}=\frac{-4-4\sqrt{46}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{46}}{2*-10}=\frac{-4+4\sqrt{46}}{-20} $
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