4x+6(2x-1)+19=8+3(x-7)

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Solution for 4x+6(2x-1)+19=8+3(x-7) equation: 



4x+6(2x-1)+19=8+3(x-7)

We move all terms to the left:

4x+6(2x-1)+19-(8+3(x-7))=0

We multiply parentheses

4x+12x-(8+3(x-7))-6+19=0



We calculate terms in parentheses: -(8+3(x-7)), so:

8+3(x-7)

determiningTheFunctionDomain
3(x-7)+8

We multiply parentheses

3x-21+8

We add all the numbers together, and all the variables

3x-13

Back to the equation:

-(3x-13)



We add all the numbers together, and all the variables

16x-(3x-13)+13=0

We get rid of parentheses

16x-3x+13+13=0

We add all the numbers together, and all the variables

13x+26=0

We move all terms containing x to the left, all other terms to the right

13x=-26

x=-26/13

x=-2

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