4x+6(x+2)=12+4(x-3)-3(x+2)

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Solution for 4x+6(x+2)=12+4(x-3)-3(x+2) equation: 



4x+6(x+2)=12+4(x-3)-3(x+2)

We move all terms to the left:

4x+6(x+2)-(12+4(x-3)-3(x+2))=0

We multiply parentheses

4x+6x-(12+4(x-3)-3(x+2))+12=0



We calculate terms in parentheses: -(12+4(x-3)-3(x+2)), so:

12+4(x-3)-3(x+2)

determiningTheFunctionDomain
4(x-3)-3(x+2)+12

We multiply parentheses

4x-3x-12-6+12

We add all the numbers together, and all the variables

x-6

Back to the equation:

-(x-6)



We add all the numbers together, and all the variables

10x-(x-6)+12=0

We get rid of parentheses

10x-x+6+12=0

We add all the numbers together, and all the variables

9x+18=0

We move all terms containing x to the left, all other terms to the right

9x=-18

x=-18/9

x=-2

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