4x+6(x+3)=32

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Solution for 4x+6(x+3)=32 equation: 



4x+6(x+3)=32

We move all terms to the left:

4x+6(x+3)-(32)=0

We multiply parentheses

4x+6x+18-32=0

We add all the numbers together, and all the variables

10x-14=0

We move all terms containing x to the left, all other terms to the right

10x=14

x=14/10

x=1+2/5

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