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4x+6+x=3(2x+2)
We move all terms to the left:
4x+6+x-(3(2x+2))=0
We add all the numbers together, and all the variables
5x-(3(2x+2))+6=0
We calculate terms in parentheses: -(3(2x+2)), so:We get rid of parentheses
3(2x+2)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
5x-6x-6+6=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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