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4x+61/2x+2=65
We move all terms to the left:
4x+61/2x+2-(65)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
4x+61/2x-63=0
We multiply all the terms by the denominator
4x*2x-63*2x+61=0
Wy multiply elements
8x^2-126x+61=0
a = 8; b = -126; c = +61;
Δ = b2-4ac
Δ = -1262-4·8·61
Δ = 13924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13924}=118$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-126)-118}{2*8}=\frac{8}{16} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-126)+118}{2*8}=\frac{244}{16} =15+1/4 $
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