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4x+7/2x=11
We move all terms to the left:
4x+7/2x-(11)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
4x*2x-11*2x+7=0
Wy multiply elements
8x^2-22x+7=0
a = 8; b = -22; c = +7;
Δ = b2-4ac
Δ = -222-4·8·7
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{65}}{2*8}=\frac{22-2\sqrt{65}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{65}}{2*8}=\frac{22+2\sqrt{65}}{16} $
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