4x+7/x+1=x+3

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Solution for 4x+7/x+1=x+3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x+7/x+1 = x+3 // - x+3

4*x-x+7/x-3+1 = 0

3*x^1+7*x^-1-2*x^0 = 0

(3*x^2-2*x^1+7*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2-2*x^1+7*x^0) = 0

x^1

3*x^2-2*x+7 = 0

3*x^2-2*x+7 = 0

DELTA = (-2)^2-(3*4*7)

DELTA = -80

DELTA < 0

x in { } 

x belongs to the empty set

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