4x+80=40x

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Solution for 4x+80=40x equation: 



4x+80=40x

We move all terms to the left:

4x+80-(40x)=0

We add all the numbers together, and all the variables

-36x+80=0

We move all terms containing x to the left, all other terms to the right

-36x=-80

x=-80/-36

x=2+2/9

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