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4x+8=1+(2x-5)
We move all terms to the left:
4x+8-(1+(2x-5))=0
We calculate terms in parentheses: -(1+(2x-5)), so:We get rid of parentheses
1+(2x-5)
determiningTheFunctionDomain (2x-5)+1
We get rid of parentheses
2x-5+1
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
4x-2x+4+8=0
We add all the numbers together, and all the variables
2x+12=0
We move all terms containing x to the left, all other terms to the right
2x=-12
x=-12/2
x=-6
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