4x+8x-64=32-4x

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Solution for 4x+8x-64=32-4x equation: 



4x+8x-64=32-4x

We move all terms to the left:

4x+8x-64-(32-4x)=0

We add all the numbers together, and all the variables

4x+8x-(-4x+32)-64=0

We add all the numbers together, and all the variables

12x-(-4x+32)-64=0

We get rid of parentheses

12x+4x-32-64=0

We add all the numbers together, and all the variables

16x-96=0

We move all terms containing x to the left, all other terms to the right

16x=96

x=96/16

x=6

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