4x+9/x=15

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Solution for 4x+9/x=15 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x+9/x = 15 // - 15

4*x+9/x-15 = 0

4*x^1+9*x^-1-15*x^0 = 0

(4*x^2-15*x^1+9*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^2-15*x^1+9*x^0) = 0

x^1

4*x^2-15*x+9 = 0

4*x^2-15*x+9 = 0

DELTA = (-15)^2-(4*4*9)

DELTA = 81

DELTA > 0

x = (81^(1/2)+15)/(2*4) or x = (15-81^(1/2))/(2*4)

x = 3 or x = 3/4

x in { 3/4, 3} 

x in { 3/4, 3 }

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