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4x+9=4+(5+x)
We move all terms to the left:
4x+9-(4+(5+x))=0
We add all the numbers together, and all the variables
4x-(4+(x+5))+9=0
We calculate terms in parentheses: -(4+(x+5)), so:We get rid of parentheses
4+(x+5)
determiningTheFunctionDomain (x+5)+4
We get rid of parentheses
x+5+4
We add all the numbers together, and all the variables
x+9
Back to the equation:
-(x+9)
4x-x-9+9=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
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