4x+x(3-2)-x=80

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Solution for 4x+x(3-2)-x=80 equation: 



4x+x(3-2)-x=80

We move all terms to the left:

4x+x(3-2)-x-(80)=0

We add all the numbers together, and all the variables

4x+x1-x-80=0

We add all the numbers together, and all the variables

4x-80=0

We move all terms containing x to the left, all other terms to the right

4x=80

x=80/4

x=20

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