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4x+x2=221
We move all terms to the left:
4x+x2-(221)=0
We add all the numbers together, and all the variables
x^2+4x-221=0
a = 1; b = 4; c = -221;
Δ = b2-4ac
Δ = 42-4·1·(-221)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-30}{2*1}=\frac{-34}{2} =-17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+30}{2*1}=\frac{26}{2} =13 $
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