4x-(1/4)=1/3(12x-3)

Solution for 4x-(1/4)=1/3(12x-3) equation:

4x-(1/4)=1/3(12x-3)

We move all terms to the left:

4x-(1/4)-(1/3(12x-3))=0


Domain of the equation: 3(12x-3))!=0

x∈R


We add all the numbers together, and all the variables

4x-(1/3(12x-3))-(+1/4)=0

We get rid of parentheses

4x-(1/3(12x-3))-1/4=0

We calculate fractions


4x+()/144x+(-3x1/144x=0

We multiply all the terms by the denominator


4x*144x+(-3x1+()=0


We calculate terms in parentheses: +(-3x1+(), so:

-3x1+(

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)


Wy multiply elements

576x^2+(-3x)=0

We get rid of parentheses

576x^2-3x=0

a = 576; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·576·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*576}=\frac{0}{1152}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*576}=\frac{6}{1152}
=1/192
$