4x-(11+3x)=7(x-2)+14

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Solution for 4x-(11+3x)=7(x-2)+14 equation: 



4x-(11+3x)=7(x-2)+14

We move all terms to the left:

4x-(11+3x)-(7(x-2)+14)=0

We add all the numbers together, and all the variables

4x-(3x+11)-(7(x-2)+14)=0

We get rid of parentheses

4x-3x-(7(x-2)+14)-11=0



We calculate terms in parentheses: -(7(x-2)+14), so:

7(x-2)+14

We multiply parentheses

7x-14+14

We add all the numbers together, and all the variables

7x

Back to the equation:

-(7x)



We add all the numbers together, and all the variables

-6x-11=0

We move all terms containing x to the left, all other terms to the right

-6x=11

x=11/-6

x=-1+5/6

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