4x-(2x+1)=8+6(x+1)

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Solution for 4x-(2x+1)=8+6(x+1) equation:



4x-(2x+1)=8+6(x+1)
We move all terms to the left:
4x-(2x+1)-(8+6(x+1))=0
We get rid of parentheses
4x-2x-(8+6(x+1))-1=0
We calculate terms in parentheses: -(8+6(x+1)), so:
8+6(x+1)
determiningTheFunctionDomain 6(x+1)+8
We multiply parentheses
6x+6+8
We add all the numbers together, and all the variables
6x+14
Back to the equation:
-(6x+14)
We add all the numbers together, and all the variables
2x-(6x+14)-1=0
We get rid of parentheses
2x-6x-14-1=0
We add all the numbers together, and all the variables
-4x-15=0
We move all terms containing x to the left, all other terms to the right
-4x=15
x=15/-4
x=-3+3/4

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