4x-(2x+3)(3x-3)=49-(6x-1)(x-2)

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Solution for 4x-(2x+3)(3x-3)=49-(6x-1)(x-2) equation: 



4x-(2x+3)(3x-3)=49-(6x-1)(x-2)

We move all terms to the left:

4x-(2x+3)(3x-3)-(49-(6x-1)(x-2))=0

We multiply parentheses ..

-(+6x^2-6x+9x-9)+4x-(49-(6x-1)(x-2))=0



We calculate terms in parentheses: -(49-(6x-1)(x-2)), so:

49-(6x-1)(x-2)

determiningTheFunctionDomain
-(6x-1)(x-2)+49

We multiply parentheses ..

-(+6x^2-12x-1x+2)+49

We get rid of parentheses

-6x^2+12x+1x-2+49

We add all the numbers together, and all the variables

-6x^2+13x+47

Back to the equation:

-(-6x^2+13x+47)



We get rid of parentheses

-6x^2+6x^2+6x-9x-13x+4x+9-47=0

We add all the numbers together, and all the variables

-12x-38=0

We move all terms containing x to the left, all other terms to the right

-12x=38

x=38/-12

x=-3+1/6

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